Answer:
At STP (standard temperature and pressure), which is 0°C (273.15K) and 1 atm, the volume of a gas is 22.4 L. Since the volume remains constant in this case, we can use the combined gas law to solve for the pressure at -185°C (88.15K):
(P1/T1) = (P2/T2)
Substituting in the values we know:
(1 atm / 273.15K) = (P2 / 88.15K)
Solving for P2:
P2 = (1 atm / 273.15K) * 88.15K
P2 = 0.322 atm
Therefore, the pressure of the gas at -185°C will be approximately 0.322 atm.