Question

100 POINTS help please :)

What is the hydroxide ion concentration and the pH of 0.035 M Sr(OH)2 at 25 °C?

Answer 1

the pH of the solution is:

pH = 14 - pOH = 14 - 1.15 = 12.85

Step-by-step explanation:

Sr(OH)2 dissociates into Sr2+ and 2 OH- ions in water. Since it is a strong base, it dissociates completely in water.

The hydroxide ion concentration can be calculated as follows:

[OH-] = 2 × 0.035 M = 0.07 M

The pH of the solution can be calculated using the formula:

pH = 14 - pOH

where pOH is the negative logarithm of the hydroxide ion concentration:

pOH = -log[OH-] = -log(0.07) = 1.15

Therefore, the pH of the solution is:

pH = 14 - pOH = 14 - 1.15 = 12.85