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1 vote
William has a bag of 240 candies that are

one fourth chocolate, one third caramel,
and the rest are butterscotch. How many
of each kind of candies are there?

User Kyle Walsh
by
8.1k points

2 Answers

0 votes
Let's start by finding the fraction of candies that are butterscotch:

Fraction of butterscotch candies = 1 - (1/4) - (1/3) = 7/12

We know that there are 240 candies in total, so we can use this fraction to find the number of butterscotch candies:

Number of butterscotch candies = (7/12) x 240 = 140

Now we need to find the number of chocolate and caramel candies. We can use the fractions given in the problem to set up a system of equations:

Number of chocolate candies = (1/4) x 240 = 60
Number of caramel candies = (1/3) x 240 = 80

Therefore, there are 60 chocolate candies, 80 caramel candies, and 140 butterscotch candies in the bag.
User Pdc
by
8.5k points
2 votes

Answer:

William has 60 chocolate candies, 80 caramel candies, and 100 butterscotch candies.

Explanation:

Let's begin by calculating the total number of butterscotch candies. We know that the bag has 240 candies, and we already know the proportions of chocolate and caramel candies:

Chocolate candies: 1/4 * 240 = 60

Caramel candies: 1/3 * 240 = 80

Therefore, the number of butterscotch candies is:

Butterscotch candies: 240 - 60 - 80 = 100

So William has 60 chocolate candies, 80 caramel candies, and 100 butterscotch candies.

User Steventnorris
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8.5k points