Question

how much heat q2 is transferred to the skin by 25.0 g of steam onto the skin? the heat of vaporization for steam is l

Answer 1

The heat transferred to the skin by 25.0 g of steam is calculated as 56.5 kJ, using the formula Q = m × Lv with the latent heat of vaporization of water being 2.26 × 10³ J/g.

Step-by-step explanation:

You've asked how much heat (Q) is transferred to the skin by 25.0 g of steam when it condenses on the skin, assuming the latent heat of vaporization is given as a value (Lv). To calculate this, we can use the equation Q = m × Lv, where 'm' is the mass of the steam and 'Lv' is the latent heat of vaporization. The latent heat of vaporization for water is 2.26 × 10³ J/g.

Therefore, the heat transferred (Q) would be Q = (25.0 g) × (2.26 × 10³ J/g) = 56500 J. So, 56.5 kJ of heat is transferred to the skin by 25.0 g of steam condensing on it.

Answer 2

The amount of heat transferred to the skin by 25.0 g of steam can be calculated using the formula Q = m Lv, where Q is the heat transferred, m is the mass of the steam, and Lv is the latent heat of vaporization of steam. Given the values Lv = 2.26 × 10³ J/g and m = 25.0 g, the heat transferred is 5.65 x 10⁴ J.

Step-by-step explanation:

Heat Transfer from Steam to Skin

The amount of heat transferred to the skin by 25.0 g of steam can be calculated using the formula Q = m Lv, where Q is the heat transferred, m is the mass of the steam, and Lv is the latent heat of vaporization of steam.

Given that the heat of vaporization for steam is Lv = 2.26 × 10³ J/g, and the mass of steam is m = 25.0 g, we can substitute these values into the formula to find Q = (25.0 g) x (2.26 × 10³ J/g) = 5.65 x 10⁴ J. Therefore, 5.65 x 10⁴ Joules of heat is transferred to the skin by 25.0 g of steam.