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How much heat is required to raise the temperature of 20.0 g of iron from 26.0 °C to 72.30 °C? (specific heat of iron = 0.444 J/(g°C)

User Ventu
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2 Answers

1 vote

Answer:

Q = 20.0 g * 0.444 J/(g°C) * (72.30 °C - 26.0 °C)

Q = 20.0 g * 0.444 J/(g°C) * 46.30 °C

Q = 20.0 g * 20.5032 J/g

Q = 410.06 J

Step-by-step explanation:

User Mrhd
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7.6k points
6 votes

The amount of heat required to raise the temperature of a substance can be calculated using the following formula:

Q = m * c * ΔT

Where:

Q = heat (in Joules)

m = mass of the substance (in grams)

c = specific heat of the substance (in J/(g°C))

ΔT = change in temperature (in °C)

Substituting the given values into the formula, we get:

Q = 20.0 g * 0.444 J/(g°C) * (72.30 °C - 26.0 °C)

Q = 20.0 g * 0.444 J/(g°C) * 46.30 °C

Q = 20.0 g * 20.5032 J/g

Q = 410.06 J

User Alexey Tseitlin
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8.4k points