Question

PLEASE ANSWER!!!! 25 POINTS!!!!!!
One mole of ideal gas occupies L at STP

Answer 1

22.4Liters

Step-by-step explanation:

An Ideal Gas, at STP occupies approximately 22.4 Liters of space.

This is often a standard relationship that many instructors will simply expect you to know, so it is something that you may want to memorize. However, it can be calculated if one knows (or can lookup and find) the value of the Ideal Gas constant, R, the Ideal Gas Law
`PV=nRT`, and the values of Temperature and Pressure at STP.

STP

The Standard Pressure is 1atm, and the Standard Temperature is 273K (0 degrees Celsius -- but Temperatures in the Ideal Gas Law need to be measured in Kelvin).

n & R

Given from the question that it is "one mole of ideal gas," n=1 mol.

Be mindful that R can be measured using a few different units, and since you want the space that the gas occupies in "L" (liters), you'll want a version of R which uses units of liters:

`R=0.0821(L\cdot atm)/(mol \cdot K)`

There are other units here, but they will cancel out as we include them in the Ideal Gas Law.

Solving for V

`PV=nRT`

`(1atm)V=(1mol)(0.0821(L\cdot atm)/(mol \cdot K))(273K)`

`V=((1mol)(0.0821(L\cdot atm)/(mol \cdot K))(273K))/(1atm)`

Observe that many of the units match and cancel, leaving just units of Liters...

`V=22.4133L`

Now, for this particular problem, they don't specify how many significant digits there are, or what they want out of an answer here. In my experience, it is common to round this result to 3 significant digits. I've been working with 3 significant digits for R and the temperature conversion, so I'll continue to do so here:

V=22.4L