Question

An electron moves horizontally at a speed of 200 m.s1 into a magnetic field of 0,5T that lies perpendicular to the motion of the electron.

7.1. Describe the motion of the electron on entering the magnetic field.
7.2.Calculate the force exerted on the electron
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Answer 1

Step-by-step explanation:

In this situation, the magnetic force supplies the centripetal force Fc=mv2r.

Noting that the velocity is perpendicular to the magnetic field, the magnitude of the magnetic force is reduced to F=qvB.

Because the magnetic force F supplies the centripetal force Fc,

we have

qvB=mv2r.

11.4

Solving for r yields