Question

A line with a slope of 3/2 passes through (-1,-1). Write the equation of the line in standard form.

A.
3x + 2y = 2
B.
y = 3/2x + 1/2
C.
y + 1 = 3/2(x + 1)
D.
3x - 2y = - 1

Answer 1

Explanation:

Using point slope calculate the equation:

y - -1 = 3/2 (x - -1)

y + 1 = 3/2(x + 1)

y + 1 = 3/2 x + 3/2

y + 1 -1 = 3/2 x + 3/2 - 1

y = 3/2 x + .5

Standard form is no fractions or decimals and the x coordinate cannot be negative.

Multiply the equation by 2 to clear the 3/2.

2y = 3x + 1

Then to get standard form AX + BY = C

Move 3x to the left which changes its sign:

-3x + 2y = 1

Multiply the entire equation by a -1 to make the x cordinate positive.

3x - 2y = -1

Choice D