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A 4.69x10^2 g block of metal absorbs 5025 J of heat when its temperature changes from 20°C to 30°C. Calculate the specific heat of the metal.

User McRui
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Answer: The specific heat of a substance is the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius. The formula for calculating the specific heat is:

q = mcΔT

where q is the amount of heat absorbed by the metal, m is the mass of the metal, c is the specific heat of the metal, and ΔT is the change in temperature of the metal.

Substituting the given values, we have:

5025 J = (0.469 kg) c (30°C - 20°C)

Simplifying and solving for c, we get:

c = 5025 J / (0.469 kg * 10°C)

c = 1070.1 J/(kg*C)

Therefore, the specific heat of the metal is 1070.1 J/(kg*C)
User Jheanell
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