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How many milliliters of 11.5 M HCl(aq) are needed to prepare 585.0 mL of 1.00 M HCl(aq)?
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3 votes
How many milliliters of 11.5 M HCl(aq) are needed to prepare 585.0 mL of 1.00 M HCl(aq)?

User Espen Burud
by
7.8k points

1 Answer

3 votes

Answer:

72.174mL

Explanation:

M1V1=M2V2

V1=M2V2 over M1=

830 × 1 over 11.5 = 72.174mL

User Sneep
by
8.2k points
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