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a 57kg woman is in an elevator accelerating upward at 1.25m/s what is the normal force acting on her?
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11 votes
11 votes
a 57kg woman is in an elevator accelerating upward at 1.25m/s what is the normal force acting on her?

User Or Neeman
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3.2k points

1 Answer

14 votes
14 votes

Answer: Fn = 630 N

Step-by-step explanation:

ΣFy = Fn - mg = ma (The sum of the forces in the y-direction must equal mass * acceleration in the y direction)

Fn = mg + ma

Fn = m(g + a)

Fn = (57 kg)(9.8 m/s^2 + 1.25 m/s^2)

Fn = 630 N

User Shastick
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3.2k points
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