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Ella invests £7000 for 2 years in an account paying compound interest.

In the first year, the rate of interest is 3%
In the second year, the rate of interest is 1.5%

Work out the value of Ella's investment at the end of 2 years.

1 Answer

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Explanation:

To calculate the value of Ella's investment at the end of 2 years, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

where A is the final amount, P is the principal (initial amount), r is the annual interest rate as a decimal, n is the number of times the interest is compounded per year, and t is the time in years.

For the first year, we have:

P = £7000

r = 0.03 (3% as a decimal)

n = 1 (compounded annually)

t = 1 (one year)

Substituting these values into the formula, we get:

A₁ = £7000(1 + 0.03/1)^(1x1)

A₁ = £7210

Therefore, the investment is worth £7210 after one year.

For the second year, we have:

P = £7210 (the new principal after one year)

r = 0.015 (1.5% as a decimal)

n = 1 (compounded annually)

t = 1 (one year)

Substituting these values into the formula, we get:

A₂ = £7210(1 + 0.015/1)^(1x1)

A₂ = £7323.15

Therefore, the investment is worth £7323.15 at the end of two years.

Therefore, the value of Ella's investment at the end of 2 years is £7323.15.

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