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(a) how wide is a single slit that produces its first minimum for 636-nm light at an angle of 25.0°?

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Answer:

If the slits are separated by d then s / d where s is the difference in the wave path between opposite sides of the slit

(a diagram would be useful here)

This can be expressed by:

sin θ = (λ / 2) / d where θ is the angle of diffraction

If d is the width of the slit then

d = λ / (2 sin θ) = 6.36E-7 / (.845) = 7.52E-7 m = 7.52E-5 cm

User Jithesh Jose
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