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A pyramid has a rectangular base with edges of length 10 and 24. The vertex of the pyramid is 13 units directly above the center of the base. What is the total SURFACE AREA of the pyramid?

User Wako
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1 Answer

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Volume= 1/3( 10*24*13)=1040 cubic units.

To find surface area slant ht is required.

Let slant ht attached to sides 10 and 24 are h1 and h2.

h1 = √(12^2+13^2)= 17.69 units.

Surface area of slant surfaces attached to side 10 is = 1/2(10*17.69)*2 ( for two identical opposite surfaces))

=176.9 sq units.

Similarly h2 =√(5^2+13^2)= 13.93 units.

Surface area of slant surfaces attached to side 24 is= 1/2(24*13.93)*2= 334.32 sq units.

Total surface area = 176.9+334.32=511.22 sq units 2

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User Steven Musumeche
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