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The demand equation for a product is p = 29 -0.01q

Write the revenue as a function of q and find the qunatity that maximizes revenue
R(q) =
The quantity that maximizes revenue is _____________________
The price of each item at this production level is $________________
The total revenue at this price is $_______________________

1 Answer

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Final answer:

The revenue function, based on the given demand equation, is R(q) = 29q - 0.01q^2. The quantity that maximizes revenue is 1450 units. At this production level, the price per item is $14.50, and the total revenue at this price is $42,025.

Step-by-step explanation:

The demand equation for a product is given by p = 29 - 0.01q, where p is the price in dollars and q is the quantity of products sold. To write the revenue function R(q), we multiply the price p by the quantity q, hence:

R(q) = p × q = (29 - 0.01q) × q = 29q - 0.01q2.

To find the quantity q that maximizes revenue, we need to find the vertex of the parabola, since the coefficient of the q2 term is negative. The vertex formula for a parabola y = ax2 + bx + c is x = -b/(2a), and in this case:

q = -(-29)/(2 × (-0.01)) = 1450.

Now we find the price at this quantity level:

p = 29 - 0.01(1450) = 29 - 14.5 = $14.50.

The total revenue at this price is:

R(1450) = 29(1450) - 0.01(14502) = $42,025.

User Ivan Fazaniuk
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