Question

Please solve and show work for the following: In △ABC, m∠A = 40, m∠C = 115, and b = 8. Find a to the nearest tenth.

Answer options:

F 12.2
G 11.3
H 5.7
J 5.3

Answer 1

To find the length of side a in triangle ABC, we can use the law of sines:

a/sin(A) = b/sin(B)

We know that m∠A = 40, b = 8, and m∠C = 115. We can find m∠B by using the fact that the sum of the angles in a triangle is 180 degrees:

m∠A + m∠B + m∠C = 180

40 + m∠B + 115 = 180

m∠B = 25

Now we can plug in the values we know into the law of sines and solve for a:

a/sin(40) = 8/sin(25)

a = sin(40) * 8 / sin(25)

a ≈ 11.3 (rounded to the nearest tenth)

Therefore, the length of side a in triangle ABC is approximately 11.3 units, which corresponds to answer option G.