Answer:Let the cost of an orange and that of a mango during the first market day be Ksh. x and Ksh. y respectively.
From the first market day:
30x + 12y = 936
From the second market day:
15(1.2x) + 20(3/4y) = 780
Simplifying the second equation:
18x + 15y = 780
(ii) Using matrix to find the cost of an orange and that of a mango in the first market day:
Rewriting the equations in matrix form:
|30 12| |x| |936|
|18 15| x |y| = |780|
Multiplying the matrices:
|30 12| |x| |936|
|18 15| x |y| = |780|
|30x + 12y| |936|
|18x + 15y| = |780|
Using matrix inversion:
| x | |15 -12| |936 12|
| y | = | -18 30| x |780 15|
|x| |270 12| |936 12|
| | = |-360 30| x |780 15|
|y|
Simplifying the matrix multiplication:
|x| |1194| |12|
| | = | 930| x |15|
|y|
Therefore, the cost of an orange in the first market day was Ksh. 39 and the cost of a mango in the first market day was Ksh. 63.
(iii) Calculation of the total amount of money realized for the sales:
On the second market day, Fatuma bought 15 oranges and 20 mangoes.
Cost of 15 oranges = 15(1.2x) = 18x
Cost of 20 mangoes = 20(3/4y) = 15y
Total cost of fruits bought on the second market day = 18x + 15y = 18(39) + 15(63) = Ksh. 1629
Profit earned on 15 oranges at 10% = 1.1(1.2x)(15) - (1.2x)(15) = 0.18x(15) = 2.7x
Profit earned on 20 mangoes at 15% = 1.15(3/4y)(20) - (3/4y)(20) = 0.15y(20) = 3y
Total profit earned = 2.7x + 3y
Total amount of money realized for the sales = Total cost + Total profit
= Ksh. 1629 + 2.7x + 3y.
Explanation: