Answer:
- (n + 3)(n + 2) or n² + 5n + 6
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The factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n:
- n! = n × (n - 2) × (n - 3) × ... × 2 × 1
As per above mentioned definition we see that:
- (n + 3)! = (n + 3) × (n + 2) × (n + 1)!
Hence the quotient of (n + 3)! and (n + 1)! is:
- (n + 3)(n + 2) or n² + 5n + 6