Answer: So, the value of the function f(x) = 2x + 3x^2 when x = 1/3 is 1.
Step-by-step explanation: To evaluate the function f(x) = 2x + 3x^2 at x = 1/3, we can substitute the value of x into the function. This gives us:
f(1/3) = 2(1/3) + 3(1/3)^2
Solving this expression following the order of operations, we first solve the exponent:
f(1/3) = 2(1/3) + 3(1/9)
Then we solve the multiplication:
f(1/3) = 2/3 + 3/9
= 6/9 + 3/9
= 9/9
= 1
So, the value of the function f(x) = 2x + 3x^2 when x = 1/3 is 1.