Answer:
The ionic equation to show the dissociation of ions in aqueous copper(II) bromide is:
CuBr2 (aq) → Cu2+ (aq) + 2Br- (aq)
In this equation, CuBr2 represents the copper(II) bromide compound that dissociates into Cu2+ and Br- ions when it is dissolved in water (represented by "aq" for aqueous). The Cu2+ ion has a positive charge of 2+ and the Br- ion has a negative charge of 1-.