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How many grams of zinc would you need to produce 8.08 grams of hydrogen

User Muller
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Answer:

The reaction between zinc and hydrochloric acid produces hydrogen gas according to the following equation:

Zn + 2HCl → ZnCl2 + H2

This equation tells us that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas. The molar mass of zinc is 65.38 g/mol, and the molar mass of hydrogen is 1.008 g/mol.

Using this information, we can set up the following proportion to find the number of grams of zinc needed to produce 8.08 grams of hydrogen:

1 mole Zn / 2 moles H2 = 65.38 g Zn / 1 mole Zn

x grams Zn / 8.08 g H2 = 65.38 g Zn / 1 mole Zn

Solving for x, we get:

x = (8.08 g H2) x (1 mole Zn / 2 moles H2) x (65.38 g Zn / 1 mole Zn)

x = 261.7 g

Therefore, you would need 261.7 grams of zinc to produce 8.08 grams of hydrogen.

Step-by-step explanation:

User Amir Jalali
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