Question

How many moles of CaCl, are required to make 1.15 L of a 2.3 M solution?

Answer 1

To calculate the moles of CaCl2 required, we need to use the formula:

moles = concentration (M) x volume (L)

Given that the volume is 1.15 L and the concentration is 2.3 M, we can calculate the moles of CaCl2 required as follows:

moles = 2.3 M x 1.15 L

moles = 2.645 mol

Therefore, we need 2.645 moles of CaCl2 to make 1.15 L of a 2.3 M solution.