Answer:
a) 15, 18, 27, 48, 52, 86, 103
b) Minimum number = 15
c) Maximum number = 103
d) Median = 48
e) First quartile = 18
f) Third quartile = 86
g) Interquartile range = 68
Explanation:
Part a
To write the data from least to greatest, arrange the numbers in ascending order:
- 15, 18, 27, 48, 52, 86, 103

Part b
The minimum number in a set of data is the smallest value.
Therefore, the minimum number of animals is 15.

Part c
The maximum number in a set of data is the greatest value.
Therefore, the maximum number of animals is 103.

Part d
The median of a set of data is the middle value when all data values are placed in order of size.

Therefore, the median is the fourth number, which is 48.

Part e
The lower quartile (Q₁) is the median of the data values to the left of the median.

Therefore, the median of the first half of the data is 18.

Part f
The lower quartile (Q₃) is the median of the data values to the right of the median.

Therefore, the median of the second half of the data is 86.

Part g
The interquartile range (IQR) is the difference between the third quartile (Q₃) and the first quartile (Q₁).

Therefore, the interquartile range is 68.