Answer:Assuming that the basketball is dropped from rest and bounces back up to its initial height of 4 feet, we can use the equations of motion to find the distance and displacement.
The distance traveled by the basketball is the total length of the path it travels, which can be calculated by adding up the distance traveled during each phase of the motion. During the first phase, the ball falls from a height of 4 feet to the ground, a distance of 4 feet. During the second phase, the ball bounces back up from the ground to a height of 4 feet, covering the same distance of 4 feet. Therefore, the total distance traveled by the basketball is:
Distance = 4 + 4 = 8 feet
The displacement of the basketball, on the other hand, is the straight-line distance between its initial and final positions. Since the basketball returns to its initial height of 4 feet, its displacement is equal to zero. Therefore:
Displacement = 0 feet
Step-by-step explanation: