Question

Passing through (3, 4) and perpendicular to the line whose equation is y=1/9x+8; slope-intercept form

Answer 1

y = -9x + 31

Explanation:

We can find the slope of the second line using the formula

`m_(2)=-(1)/(m_(1) )`, where m2 is the slope of the second line and m1 is the slope of the first.

Thus, since 1/9 is the slope of the first line, we have

`m_(2)=-(1)/((1/9)) \\m_(2)=-9`

Since the slope intercept form is y = mx + b, where b is the y-intercept, we need to it in the second line by plugging in (3, 4) for x and y and -9 for m:

`4=-9(3)+b\\4=-27+b\\31=b`