Question

Find the product. Assume that no denominator has a value of 0.
6r+3/r+6 • r^2 + 9r +18/2r+1

Answer 1

Explanation:

We can simplify the fractions first:

(3r + 9)(r+6) / (r+6) = 3r + 9

6r + 3 / (r + 6) = 3(2r + 1) / (r + 6)

(r^2 + 9r + 18) / (2r + 1) = (r^2 + 6r + 3r + 18) / (2r + 1) = [(r+3)(r+6)] / (2r + 1)

So the expression becomes:

[3(2r + 1) / (r + 6)] * [(r+3)(r+6) / (2r + 1)]

We can now cancel out the common factors:

[3 * (r+3)] = 3r + 9

Therefore, the simplified product is:

(3r + 9)(r+6) / (r+6) = 3r + 9