2 Answers

Pjobs · Answer 1 · 2024-05-31T23:35:36+0000

Answer:

(3)/(t - 1)

Explanation:

$(t^2 - 2t - 3)/(t^2 - 1) \cdot (3t - 3)/(t^2 - 4t + 3) =$

Start by factoring every numerator and denominator.

$= ((t - 3)(t + 1))/((t + 1)(t - 1)) \cdot (3(t - 1))/((t - 3)(t - 1))$

Every factor that exists in both a numerator and denominator can be eliminated.

$= (1)/(t - 1) \cdot (3)/(1)$

Multiply numerators together. Multiply denominators together.

= (3)/(t - 1)

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