Answer:
y = 5x + 11
Explanation:
We know that the given line y=5x+3 has a slope of 5, because it is in the form y=mx+b where m is the slope.
Since we want to find a line parallel to this line, it will have the same slope of 5.
Using the point-slope form of a line, we can write the equation for the line passing through the point (-1,6) with slope 5 as:
y - 6 = 5(x - (-1))
Simplifying:
y - 6 = 5x + 5
y = 5x + 11
Therefore, the equation of the line parallel to y=5x+3 that passes through the point (-1,6) is y=5x+11.