Question

The distance between Point A and Point B along a jogging track is 24 Km. Gerald

starts from Point A and jogs at a speed of 6 Km/h. Shaun starts from Point B 30 min
after Gerald but reaches Point A 30 min earlier. What is Shaun's average speed?

Answer 1

Answer: Let's start by finding out the time it takes for Gerald to jog from Point A to Point B. We can use the formula:

distance = rate x time

to do this. Since the distance between Point A and Point B is 24 km and Gerald's speed is 6 km/h, we have:

24 = 6t

where "t" is the time it takes for Gerald to jog from Point A to Point B. Solving for "t", we get:

t = 4

So Gerald takes 4 hours to jog from Point A to Point B.

Now, let's look at Shaun's journey. We know that he starts 30 minutes after Gerald and reaches Point A 30 minutes earlier than Gerald. This means that the time it takes for Shaun to travel from Point B to Point A is 3.5 hours (i.e., 4 hours - 0.5 hours + 0.5 hours).

Using the formula distance = rate x time again, we can find out Shaun's average speed:

24 = rate x 3.5

simplifying, we get:

rate = 6.857 km/h

So Shaun's average speed is 6.857 km/h (or approximately 6.86 km/h rounded to two decimal places).

Answer 2

8 km/h

Explanation:

You want to know Shaun's average speed on a 24 km jogging track if Gerald jogged at 6 km/h for the distance, while Shaun left half and hour later and arrived half an hour earlier than Gerald.

Gerald's time

The time it took Gerald to complete the distance is found from ...

time = distance/speed

time = (24 km)/(6 km/h) = (24/6) h = 4 h

Shaun's time

Shaun left half an hour later than Gerald, and completed the trip half an hour before Gerald did. Shaun's time was 1 hour less than Gerald's, so was ...

4 h -1 h = 3 h

Shaun's speed

Shaun's average speed can be found from ...

speed = distance/time

speed = (24 km)/(3 h) = 8 km/h

Shaun's average speed was 8 km/h.