Answer: We can use the formula Distance = Average speed x time to verify whether Dr Seroto left his office at exactly 10:50.
Let t be the time Dr Seroto left his office. Then, the time he arrived at the school can be expressed as:
t + (Distance/Average speed) = 11:20
We know that the distance is 45 km and the average speed is 100 km/hour. Substituting these values, we get:
t + (45/100) = 11:20
We need to convert the time on the right-hand side to hours. 11:20 can be written as:
11 + 20/60 = 11.33 hours
Substituting this value, we get:
t + 0.45 = 11.33
Solving for t, we get:
t = 11.33 - 0.45
t = 10.88 hours
This is not equal to 10:50, which is 10.83 hours. Therefore, Dr Seroto did not leave his office at exactly 10:50.