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3.3 Dr Seroto travelled from his office directly to the school 45 km away. He travelled at an average speed of 100 km per hour and arrived at the school at 11:20. Verify, showing ALL calculations, whether Dr Seroto left his office at exactly 10:50. The following formula may be used: Distance = average speed x time


distance= average sped * time


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Answer: We can use the formula Distance = Average speed x time to verify whether Dr Seroto left his office at exactly 10:50.

Let t be the time Dr Seroto left his office. Then, the time he arrived at the school can be expressed as:

t + (Distance/Average speed) = 11:20

We know that the distance is 45 km and the average speed is 100 km/hour. Substituting these values, we get:

t + (45/100) = 11:20

We need to convert the time on the right-hand side to hours. 11:20 can be written as:

11 + 20/60 = 11.33 hours

Substituting this value, we get:

t + 0.45 = 11.33

Solving for t, we get:

t = 11.33 - 0.45

t = 10.88 hours

This is not equal to 10:50, which is 10.83 hours. Therefore, Dr Seroto did not leave his office at exactly 10:50.

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