Question

Given the system of inequalities: 4x – 5y < 1 one-halfy – x < 3 which shows the given inequalities in slope-intercept form? y < four-fifthsx – one-fifth y < 2x 6 y > four-fifthsx – one-fifths y < 2x 6 y > negative four-fifthsx one-fifth y > 2x 6

Answer 1

The inequalities in slope-intercept form are y > (4/5)x - 1/5 and y < 2x + 6.

Step-by-step explanation:

The given system of inequalities is:

4x – 5y < 1

1/2y – x < 3

To write these inequalities in slope-intercept form, we need to isolate y on one side of each equation. The slope-intercept form of an equation is y = mx + b where m is the slope and b is the y-intercept.

For the first inequality, rearrange it to get:

-5y < -4x + 1

y > (4/5)x - 1/5

So, the first given inequality in slope-intercept form is y > (4/5)x - 1/5.

For the second inequality, rearrange it to get:

1/2y < x + 3

y < 2x + 6

So, the second given inequality in slope-intercept form is y < 2x + 6.