Question

A chemical reaction produced 125mL of CO2. What was the mass of the gas produced? ​

Answer 1

0.25g

Step-by-step explanation:

Dimensional analysis.

Assuming the reaction is taking place at standard temperature and pressure (STP, 1 atm at 298.15K or 25 C), 1 mol of gas occupies 22.4L.

We are given the volume of the gas, with this we are able to find its number of moles.

125mL = 0.125L

`0.125 L * (1 mol)/(22.4 L)`

= 0.0056mol

With the number of moles we can simply multiply by the molecules molar mass.

CO2 = 12.011 g/mol+ 2*15.999 g/mol

CO2 = 44.009g / mol

`44.009 (g CO2)/(mol) * 0.0056mol CO2\\\\=0.25 g CO2`