Question

Using a cable with a tension of 1350 n, a tow truck pulls a car 5.00 km along a horizontal roadway. (a) how much work does the cable do on the car if it pulls horizontally

Answer 1

The work done by the cable on the car that is pulled horizontally is 6,750,000 J.

Step-by-step explanation:

To calculate the work done by the cable, we use the equation:

Work = Force × Distance × cos(theta)

In this case, the force is the tension in the cable, which is 1350 N. The distance is 5.00 km (converted to meters), and the angle (theta) is 0° because the cable is pulling horizontally. Therefore, the work done by the cable on the car is:

Work = 1350 N × 5000 m × cos(0°)

Work = 6,750,000 J

Answer 2

The work done on a car by a tow truck cable pulling with a tension of 1350 N over a horizontal distance of 5.00 km is 6,750,000 J or 6.75 MJ.

Step-by-step explanation:

To calculate the work done on a car by a tow truck pulling with a tension of 1350 N over a distance of 5.00 km horizontally, we can use the work formula Work (W) = Force (F) × Distance (d). Here, the force is applied horizontally and the distance is in the same direction as the force. Since the tension in the cable is horizontal and the car is moving horizontally, the angle (θ) between the force and the direction of motion is zero degrees. Hence, the work done can be calculated as:

W = F × d × cos(θ)

W = 1350 N × 5.00 km × cos(0°)

First, convert the distance from kilometers to meters to match the units of tension (N):
5.00 km = 5000 m

Now, compute the work done:

W = 1350 N × 5000 m × cos(0°)

W = 1350 N × 5000 m × 1

W = 6750000 J (Joules)
As such, the work done by the cable on the car is 6,750,000 J or 6.75 MJ (megaJoules).