Question

In 1910, Halley's Comet traveled close to Earth-- about 1/7 of the distance from Earth to the Sun. Earth's distance from the sun is 149.6 million kilometers.

1. How close was Halley's Comet to Earth in 1910? Create an equation to answer the question.

2. Estimate the next three years when Halley's Comet will appear.

3. The core of Halley's comet is oblong in shape, with its longest dimension 16 km long. Earth's diameter is about 12,700 km. How many times larger in diameter is Earth than Halley's comet?

Answer 1

1. 21.37 million km

2. 2061 (1986 + 76)

2137 (2061 + 76)

2213 (2137 + 76)

3. 793.75

Step-by-step explanation:

To find how close Halley's Comet was to Earth in 1910, we can use the given information that it traveled about 1/7 of the distance from Earth to the Sun.

Distance between Halley's Comet and Earth = (1/7) x distance between Earth and Sun

Distance between Halley's Comet and Earth = (1/7) x 149.6 million km

Distance between Halley's Comet and Earth = 21.37 million km

Therefore, Halley's Comet was approximately 21.37 million kilometers away from Earth in 1910.

Halley's Comet has an orbital period of approximately 76 years. Its last appearance was in 1986, so we can estimate its next three appearances as follows:

2061 (1986 + 76)

2137 (2061 + 76)

2213 (2137 + 76)

Note that these are only estimates based on the comet's previous orbital period and are subject to change based on various factors.

The core of Halley's Comet is 16 km long, so its diameter is approximately 16 km. The diameter of Earth is approximately 12,700 km.

The ratio of Earth's diameter to Halley's Comet's diameter = Diameter of Earth / Diameter of Halley's Comet

The ratio of Earth's diameter to Halley's Comet's diameter = 12,700 km / 16 km

The ratio of Earth's diameter to Halley's Comet's diameter = 793.75

Therefore, Earth's diameter is approximately 793.75 times larger than Halley's Comet's diameter.

Answer 2

a. 21.37 million km

b.

2061 (1986 + 76)

2137 (2061 + 76)

2213 (2137 + 76)

c. 793.75

Step-by-step explanation:

To find how close Halley's Comet was to Earth in 1910, we can use the given information that it traveled about 1/7 of the distance from Earth to the Sun.

Distance between Halley's Comet and Earth = (1/7) x distance between Earth and Sun

Distance between Halley's Comet and Earth = (1/7) x 149.6 million km

Distance between Halley's Comet and Earth = 21.37 million km

Therefore, Halley's Comet was approximately 21.37 million kilometers away from Earth in 1910.

Halley's Comet has an orbital period of approximately 76 years. Its last appearance was in 1986, so we can estimate its next three appearances as follows:

2061 (1986 + 76)

2137 (2061 + 76)

2213 (2137 + 76)

Note that these are only estimates based on the comet's previous orbital period and are subject to change based on various factors.

The core of Halley's Comet is 16 km long, so its diameter is approximately 16 km. The diameter of Earth is approximately 12,700 km.

Ratio of Earth's diameter to Halley's Comet's diameter = Diameter of Earth / Diameter of Halley's Comet

Ratio of Earth's diameter to Halley's Comet's diameter = 12,700 km / 16 km

Ratio of Earth's diameter to Halley's Comet's diameter = 793.75

Therefore, Earth's diameter is approximately 793.75 times larger than Halley's Comet's diameter.