Question

Expand and evaluate the series.

∑6n=13n
{
,
,
,
,
,
}

S6=

Answer 1

The series ∑6n=1 3n is a sum of the first 6 terms of the sequence 3n, which starts with n = 1 and increases by 3 for each successive term. Therefore, the first 6 terms of the sequence are:

3(1), 3(2), 3(3), 3(4), 3(5), 3(6)

which simplify to:

3, 6, 9, 12, 15, 18

The sum of these terms is:

∑6n=1 3n = 3 + 6 + 9 + 12 + 15 + 18 = 63

Therefore, S6, the sum of the first 6 terms of the series, is 63.