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A spring scale hung from the ceiling stretches by 5.9 cm

when a 1.6 kg
mass is hung from it. The 1.6 kg
mass is removed and replaced with a 2.1 kg
mass.
Part A
What is the stretch of the spring?
Express your answer with the appropriate units.

User Geh
by
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1 Answer

3 votes

The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.

The stretch of the spring is given by:

stretch = (mass x gravity x length) / (spring constant)

where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).

We can rearrange this equation to solve for the stretch of the spring:

stretch = (mass x gravity x length) / (spring constant)

length = (spring constant x stretch) / (mass x gravity)

Substituting the given values, we get:

length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)

Simplifying, we get:

length = 0.236 m

Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.

User Varada
by
8.4k points