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What is the frequency of a photon if the energy is 7.26 × 10⁻¹⁹ J? (h = 6.626 × 10⁻³⁴ J • s)

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Final answer:

The frequency of a photon with an energy of 7.26 × 10⁻¹⁹ J is found using Planck's equation, E = hf, to be 1.095 × 10¹⁴ Hz.

Step-by-step explanation:

To find the frequency of a photon when given its energy, we can use the relationship defined by the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency. We can rearrange the equation to solve for frequency: f = E/h.

Let's use the given values:
E = 7.26 × 10⁻¹⁹ J (the photon's energy) and
h = 6.626 × 10⁻³⁴ J·s (Planck's constant).

Substituting these into our equation gives us:
f = (7.26 × 10⁻¹⁹ J) / (6.626 × 10⁻³⁴ J·s) = 1.095 × 10¹⁴ Hz

The frequency of the photon is 1.095 × 10¹⁴ Hz.

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