Question

Question 14

point)
Helium gas is contained in a tank with a pressure of 14.4 MPa. If the temperature
inside the tank is 24.6 °C and the volume of the tank is 19.4 L, determine the mass,
in grams, of the helium in the tank.

Answer 1

So we gonna use the equation PV=mRT/M


P=14.4MPa
T=24.6degree c= 24.6+273=297.6K
V=19.4L


Converting MPa=9.869atm
14.4mpa=x

X=9.869x14.4MPa

X=142.1136atm
X=142atm


PV=mRT/M

142atmx19.4L=mx0.8206Latm/K/molx297.6K/
4g/mol

M=142atmx19.4Lx4g/mol/0.8206atm/k/molx297.6K

M=142x19.4x4g/0.8206x297.6

M=11019.2/244.21056

M=45.12

M=45g