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Question 2(Multiple Choice Worth 4 points)

(05.02, 05.03 MC)
Solve the system of equations.
2x + 4y = 12
3x +y = 3
(0,3)
○(1,0)
(2, 2)
(2,-3)
Question 3(Multiple Choice Worth 4 points)

User Markus L
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1 Answer

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Answer: (0,3)

x=0 ; y=3

Explanation:

To solve the system of equations:

2x + 4y = 12

3x + y = 3

We can use the method of substitution or elimination. Here we will use the substitution method:

From Equation 2, we can isolate y:

y = 3 - 3x

We can substitute this expression for y into Equation 1:

2x + 4(3 - 3x) = 12

Simplifying and solving for x:

2x + 12 - 12x = 12

-10x = 0

x = 0

Now that we have found the value of x, we can substitute it back into either Equation 1 or Equation 2 to solve for y. Here we will use Equation 2:

3(0) + y = 3

y = 3

Therefore, the solution to the system of equations is (x, y) = (0, 3).

This means that the point (0, 3) is the intersection point of the two lines represented by the given equations. To verify this, we can substitute the values of x and y into both equations and see if they are true.

User Lopper
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