Question

A reaction between phosphorus, Pa, and an excess oxygen produces tetraphosphorus decoxide. If 74.3 g phosphorus is used, how many grams of tetraphosphorus decoxide will be produced?

Write and balance the equation. Then, calculate the grams ot tetraphosphorus decoxide.
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Answer 1

Answer: P4 + 5 O2 → P4O10

74.3 grams of phosphorus will produce 220 grams of tetraphosphorus decoxide.

Step-by-step explanation:

The balanced chemical equation for the reaction between phosphorus and oxygen to produce tetraphosphorus decoxide is:

P4 + 5 O2 → P4O10

From the equation, we can see that 1 mole of phosphorus reacts with 5 moles of oxygen to produce 1 mole of tetraphosphorus decoxide.

To calculate the grams of tetraphosphorus decoxide produced, we need to convert the given mass of phosphorus to moles using its molar mass. The molar mass of phosphorus is 30.97 g/mol.

74.3 g P / (30.97 g/mol P) = 2.4 moles P

From the balanced equation, we know that 1 mole of P4O10 weighs 283.89 g/mol.

So, 2.4 moles P4O10 = 2.4 mol x 283.89 g/mol = 681.33 g

Therefore, 74.3 grams of phosphorus will produce 681.33 grams of tetraphosphorus decoxide.