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Zinc reacts with Hydrochloric Acid in a single replacement reaction. If you have 8 g of of zinc metal, what mass of each product would you produce?

User Reznor
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1 Answer

5 votes

Answer:


16.68g ZnCl_2


0.2472g H_2

Step-by-step explanation:

1.)Write equation:


Zn(aq)+HCl(aq)== > ZnCl_2(aq)+H_2(g)

2.)Balance:


Zn(aq)+2HCl(aq)== > ZnCl_2(aq)+H_2(g)

3.)Convert:


8g Zn/(1mol Zn)/(65.380g Zn)/(1mol ZnCl_2)/(1mol Zn)/(136.28g ZnCl_2)/(1mol ZnCl_2) =16.68g ZnCl_2


8g Zn/(1mol Zn)/(65.380g Zn)/(1 molH_2)/(1molZn)/(2.02g H_2)/(1mol H_2)=0.2472g H_2

(This does not include sig figs)

User MarZab
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