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A part of an mRNA molecule with the following sequence is being read by a ribosome: 5'-CCG-ACG-3' (mRNA). The charged transfer RNA molecules shown in the figure below (with their anticodons shown in the 3' to 5' direction) are available. Two of them can correctly match the mRNA so that a dipeptide can form:

tRNA Anticodon Amino Acid
GGC
Proline
CGU
Alanine
UGC
Threonine
CCG
Glycine
ACG
Cysteine
CGG
Alanine


Which of the following dipeptides will be formed?
Proline-Threonine
Glycine-Cysteine
Alanine-Alanine
Cysteine-Alanine

2 Answers

2 votes

Answer:

The dipeptide that will be formed is Proline-Threonine.

Step-by-step explanation:

The anticodon for the mRNA sequence 5'-CCG-ACG-3' is 3'-GGC-UGC-5', which matches with the tRNA molecules with anticodons 3'-GCC-5' (carrying Proline) and 3'-ACG-5' (carrying Threonine). Therefore, the dipeptide that can be formed is Proline-Threonine.

User Lukas Graf
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6 votes

Answer:

Cysteine-Alanine

Step-by-step explanation:

got it right

User Fabio Lolli
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