Question

x = 16 and y = 2, given that x is directly related to the square of y. If x = 100, what is one possible value of y?

Answer 1

One possible value of y when x = 100 is y = 5.

Explanation:

Using the direct variation formula, we know that x = ky^2, where k is a constant. Given that x = 16 and y = 2, we can solve for k:

16 = k(2)^2

k = 4

Now we can use this value of k to find y when x = 100:

100 = 4y^2

y^2 = 25

y = 5 or -5 (since the question only asks for one possible value, we can choose either solution)

Therefore, one possible value of y when x = 100 is y = 5.

Answer 2

Answer: 5

Explanation:

Since x is directly related to the square of y, we can write the equation:

x = ky^2

where k is a constant of proportionality. We can solve for k using the given values of x and y:

16 = k(2^2) -> 16 = 4k -> k = 4

Now that we know k, we can use it to find y when x = 100:

100 = 4y^2 -> 25 = y^2 -> y = ±5

Since y cannot be negative, the only possible value of y is 5. Therefore, when x = 100, y could be 5.