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Solve completely the system of equations :

x + 3y - 22 = 0 , 2x - y + 42 = 0 , x - 11y + 142 = 0.

User Loufs
by
7.5k points

1 Answer

4 votes

Answer:

x = -16/7 and y = 38/7.

Explanation:

To solve the system of equations:

x + 3y - 22 = 0 --- equation (1)

2x - y + 42 = 0 --- equation (2)

x - 11y + 142 = 0 --- equation (3)

We will use the method of substitution to find the values of x and y that satisfy all three equations.

From equation (1), we can express x in terms of y:

x = 22 - 3y --- equation (4)

We can substitute equation (4) into equation (2) and simplify:

2(22 - 3y) - y + 42 = 0

44 - 6y - y + 42 = 0

-7y = -38

y = 38/7

Now, we can substitute the value of y into equation (4) to find x:

x = 22 - 3(38/7)

x = -16/7

Therefore, the solution to the system of equations is:

x = -16/7 and y = 38/7.

User Christian Zosel
by
8.3k points