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How do you factor 2h^2-7h+5?

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Answer:

Explanation:

To factor 2h^2 - 7h + 5, we need to find two binomials of the form (ah + b)(ch + d) that multiply to give the original expression.

To do this, we can use a technique called "factoring by grouping":

Step 1: Multiply the first term by the constant term: 2h^2 * 5 = 10h^2.

Step 2: Find two factors of 10h^2 that add up to the coefficient of the middle term, -7h. We can see that -5h and -2h satisfy this condition, since -5h * 2h = -10h^2 and -5h + (-2h) = -7h.

Step 3: Rewrite the middle term -7h as the sum of -5h and -2h: -7h = -5h - 2h.

Step 4: Factor by grouping:

2h^2 - 5h - 2h + 5

h(2h - 5) - 1(2h - 5)

(h - 1)(2h - 5)

Therefore, the factorization of 2h^2 - 7h + 5 is (h - 1)(2h - 5).

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