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The objective lens and the eyepiece of a microscope are 16.5 cm apart. The objective lens has a magnification of 64× and the eyepiece has a magnification of 10 ×. Assume that the image of the objective lies very close to the focal point of the eyepiece.

Part A) Calculate the overall magnification of the microscope.
Part B) Calculate the focal length of the eyepiece.
Part C) Calculate the focal length of the objective.

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Part A) The overall magnification of the microscope is equal to the product of the magnification of the objective lens and the magnification of the eyepiece:

M = M_objective x M_eyepiece
M = 64 x 10
M = 640

Therefore, the overall magnification of the microscope is 640×.

Part B) The magnification of the eyepiece is given by:

M_eyepiece = f_objective / (f_objective + d)

where f_objective is the focal length of the objective lens, and d is the distance between the objective lens and the eyepiece. Since the image of the objective lies very close to the focal point of the eyepiece, we can assume that d is equal to the focal length of the eyepiece, which we will denote as f_eyepiece. Substituting these values into the equation above, we get:

10 = f_objective / (f_objective + f_eyepiece)

We can rearrange this equation to solve for f_eyepiece:

f_eyepiece = f_objective / 10 - 1

The magnification of the objective lens is given by:

M_objective = f_eyepiece / (f_eyepiece - d)

Substituting the value of d, we get:

M_objective = f_eyepiece / (f_eyepiece - f_eyepiece)
M_objective = 1

Therefore, the magnification of the objective lens is 1×. We can use this value to solve for f_objective:

M = M_objective x M_eyepiece
640 = 1 x 10 x (f_objective / (f_objective + f_eyepiece))

Substituting the expression for f_eyepiece that we derived earlier, we get:

640 = 10 x f_objective / (f_objective / 9)
640 = 90

Solving for f_objective, we get:

f_objective = 14.06 cm

Therefore, the focal length of the objective lens is 14.06 cm.
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