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what is the maximum acceleration of a platform that vibrates with an amplitude of 5.00 cm at a frequency of 8.90 hz?

User Fred Wu
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1 Answer

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Answer: 93.8m/s²

Step-by-step explanation:

The acceleration amplitude is given by,

aₓ = ω² * xₓ

where ω is the angular frequency and ω = 2πf

since there are 2π radians in one cycle,

acceleration can be given as

aₓ = (2π*8.90)² * ( 0.03)

aₓ = 93.8 m/s²

User Ateeb
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