Let's call the number of pennies Daran has "p" and the number of nickels he has "n".
According to the problem, the value of the coins is $0.80, or 80 cents. We can set up an equation to represent this:
0.01p + 0.05n = 0.80
We also know that Daran has 10 more nickels than pennies:
n = p + 10
We can substitute this expression for "n" into the first equation:
0.01p + 0.05(p + 10) = 0.80
Simplifying:
0.01p + 0.05p + 0.50 = 0.80
0.06p = 0.30
p = 5
Therefore, Daran has 5 pennies. We can use the expression n = p + 10 to find the number of nickels:
n = 5 + 10 = 15
Therefore, Daran has 15 nickels.