Question

Help me with this please

Answer 1

Answer: 22 ft

Explanation:

The width of the walkway is x + 6 + x = 2x + 6 ft and the height of the walkway is x + 8 + x = 2x + 8. Because the area of the walkway and pool sum up to 528
`ft^(2)`, we can get the equation

`(2x + 8)(2x + 6) = 528`

`4x^(2) +28x + 48 = 528`

`4x^(2) +28x - 480 = 0`

`x^(2) +7x - 120 = 0`

`(x-8)(x+15)=0` So x can be either 8 or -15 but x is a length so it must be positive, therefore x is 8. That means it's width is
`2x + 6 = 2(8) + 6 = 22`