The number of atoms in a sample is determined by Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole.
To determine which sample contains the most aluminum atoms, we need to convert each sample to the number of atoms of aluminum it contains.
- 3 mol Al: 3 mol x 6.022 x 10^23 atoms/mol = 1.807 x 10^24 atoms
- 30 g Al: First, we need to determine the number of moles of aluminum in 30 g. The molar mass of aluminum is approximately 27 g/mol, so 30 g Al is approximately 1.11 moles of Al. Then, we can convert to the number of atoms of aluminum: 1.11 mol x 6.022 x 10^23 atoms/mol = 6.685 x 10^23 atoms
- 1.2 x 10^24 Al atoms: This sample already gives the number of atoms of aluminum.
Therefore, the sample with the most aluminum atoms is 3 mol Al, with 1.807 x 10^24 atoms of aluminum.